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  1. ...f.equals(b) || f.equals(a)) return a; else return (F(f. subtract (a))).add(F(f. subtract (b))); } }

  2. 你可以試用看看 Subtract 的這個Function 例: DateTime.Now. Subtract (...

  3. ...應該是 BigInteger.ONE.shiftLeft(i). subtract (BigInteger.ONE) 請參考: import java.math... 是 BigInteger 下向左位移的運算 subtract 是 BigInteger 下減法的運算

  4. ...if(b.equals(b1))//b=1時傳回1 return b1; else return b.multiply(layer(b. subtract (b1)));//呼叫自己 } } 2010-03-16 18:17:45 補充: 不一定 基本上用字串去轉換...

  5. ...i) Next bbb = Now '做之後記錄時間 ttt = bbb. Subtract (aaa) Console.WriteLine(ttt.Ticks) '100 ns...

  6. ...public int add() {//Sum return this.a+this.b; } public int subtract () {// Subtract return Math.abs(this.a-this.b...

  7. ....out.println("b1 + b2 = " + cal.toString()); cal = b1. subtract (b2); System.out.println("b1 - b2 = " + cal.toString()); cal...

  8. ...記錄的時間,就會求得所要的TimeSpan mTime = Now. Subtract (nowtime) 這個TotalSeconds會精確到小數點下五位 MsgBox...

  9. 只是要計算程式的時間用datetime.now就可以了 精準度到千分之一秒 main { dim st as Datetime = datetime.now do @程式內容計算 loop dim et as datetime = datetime.now ' 印出共花了多少秒 console.writeline(et. Subtract (st).Totalseconds) }

  10. ...object sender, EventArgs e) { RemainTime = RemainTime. Subtract (SubTime); this.label_Time.Text = RemainTime....