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  1. (1) v = ? for c = r + R E1 = Rotating energy = 0.5*I*w^2 = 0.5 * 2/5 * mr^2 * [v/(R+r)]^2 = m/5 * [r/(R+r)]^2 * v^2 E2 = Kinetic energy = 0.5 * m * v^2 E3 = Potential energy = m*g*(r+R)(1-cosθ...

  2. (1) m2*g - T2 = m2*a (2) T2 - T3 = M*a/2 (Note) (3) T3 - T1 = M*a/2 (Note) (4) T1 - m1*g = m1*a Eq.(1) + Eq.(2) + Eq.(3) + Eq.(4): a = (m2-m1)/(m1+m2+M) ..... (5) Both Eq...

  3. (1) Basic concept v(center) = v(tangent) a(center) = a(tangent) (2) f = Friction f directs toward right. (3) Newton equation F + f = M*a (4) Torque equation (F - f) * R = I * Alpha = (0.5*M...

  4. I = ΣM*R^2 = R^2*ΣM = (3.15^2 + 2^2)*(3 + 2 + 2 + 4) = 13.9225 * 11 = 153.1475 kg.m^2

  5. (a)Vab=1*3=3V (b)I1=1+3/6=1.5A (c)I2=I1=1.5A (d)Vc=1.5*4=6V (e)P=6*1.5=9W

  6. 1.W = ? if L = s Q = Angle measured from P1 L = r*Q ΣFt = F(L) - m*g*sinQ = 10 - 2L - mg*sinQ = 10 - 2r*Q - mg*sinQ W = ∫Ft*dL...

  7. ... does NOT give a complete explanation to the question, and the writer showed incorrect concepts in the remarks. The remarks should...

  8. 1. Where is the diagram? 2. (a) Use momentum conservation 0.08 x 3 = (0.08 + m) x 1.6 where m is the mass of the rubber solve for m gives m = 0.07 kg (b) Force = 0.07 x 1.6/1 N = 0.112 N The force is frictional force. 3. (a) The final momentum...

  9. Is there a diagram showing the trajectories of the two particles? The magnetic force...

  10. ... at point X is greater than that at point Y, this shows the field intensity at Y is stronger than that at X. ...