...π(9)(120/360) ---------→ 《arc length = 2πr(θ/360)》 = 6π ∴ perimeter of shaded region = 6π + 9√3 = 34.4 cm (to 3 sig.fig.) (c) area of sector = π(9²)(120...
.../360⁰)=π(4.82)²(68⁰/360⁰) ∴ area of shaded part = π(4.82)²(68⁰/360⁰) - ½(4.82)²...
...πr²(60⁰/360⁰) = π*15²/6 = 225π/6 ∴ area of shaded part = 225π/6 - 225√3/4 = 225(π/6 -√3/4) So, area of...
... figure shows 4 identical circles. If the perimeter of the shaded region is 2π cm, find the area of the shaded region. A. 4(π...
Worry not, dude. It is normal for light colored eyes to change into darker colors due to the production of pigment. Sorry to break to you that you might have some European blood. Nonetheless, please make sure that you have your...
... in Figure 11, with the part which generates the solid shaded . (i) What is the diameter of the mouth of the bowl, in terms of...
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1. Correct. 2. Where is the shaded area? Didn't see it on the diagram. 3. Correct. 4. Correct. 5. Correct. 6. Correct. 7. Correct.
... - (1/4) π 6² = 36 - 9π Therefore, the area of the shaded region = 36 - (36 - 9π) = 9π (A)
