... figure shows 4 identical circles. If the perimeter of the shaded region is 2π cm, find the area of the shaded region. A. 4(π...
...πr²(60⁰/360⁰) = π*15²/6 = 225π/6 ∴ area of shaded part = 225π/6 - 225√3/4 = 225(π/6 -√3/4) So, area of...
...π(9)(120/360) ---------→ 《arc length = 2πr(θ/360)》 = 6π ∴ perimeter of shaded region = 6π + 9√3 = 34.4 cm (to 3 sig.fig.) (c) area of sector = π(9²)(120...
.../360⁰)=π(4.82)²(68⁰/360⁰) ∴ area of shaded part = π(4.82)²(68⁰/360⁰) - ½(4.82)²...
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