...local minimum point of f(x,y) (if exist) subject to the constraint g(x,y) = 0 are satisfied the equations { ∇f = λ∇g { g(x,y) = 0 For the function of three...
...; very small value) 條件二 f(x)是連續函數 implies for ANY u satisfy 0 < | u - b | < very small value => 0 <...
... a delta>0 selected to be delta=sqrt(epsilon), then for every x satisfying 0<|x-0|<delta, we have |f(x)-0|<=x...
＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝＝ 圖片參考：https://s.yimg.com/rk/HA05107138/o/541744855.png 圖片參考：https://s.yimg.com/rk/HA05107138/o/1466025878.png 圖片參考：https://s.yimg.com/rk/HA05107138/o...
How many real numbers satisfy x+1=4*atan(x)?=> (x+1)/4=atan(x)=> tan[(x+1)/4]=x=> y1(x)=tan[(x+1)/4...
﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣﹣ 圖片參考：https://s.yimg.com/rk/HA05107138/o/1180539444.png 2014-05-28 10:13:09 補充： 多謝進哥的分享. 我只是按按計數機 (√5 + 2)^(1/3) =1.618=黃金比例 所以說應該是記住的吧!
...this general solution form, one can easily provea parallelogram property that this u(x,t) will satisfy : If A, B, C, and D arevertices of a parallelogram...
1。設V是ř上的二維向量空間，T：？？五 - > V為滿足身份T ^ 2 = T-2 * ID V秀線性變換，對於任何非零向量v Vthe集= {V，T （V）}是V的基礎 2let VBE中的域F上的雙V *一個向量空間...
(a) H0 : p ≦ 0.4 H1 : p > 0.4 臨界值 = Z 0.05 = 1.645 確認是否可用常態檢定: 0.4 ± 3 √(0.4*0.6/200) = 0.4 ± 3*0.035 = 0.295 ~ 0.505 不含0與1,故可用常態檢定. 檢定的統計量 = ( 85/200 - 0.4 ) / √(0.4*0.6/200) = ( 0.425 - 0.4 ) / 0.035 ≒ 0.714 < 1.645 = 臨界值 故不拒絕H0,即...
