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  1. (a) Distance covered by satellite in one revolution round the earth = 2 x pi x (350+6370) km where pi = 3.14159..... Hence, average speed = distance/time = 2 x pi x (350+6370) /1.5 km/h (b) Similar, distance covered by satellite in one revolution = 2 x pi x (h+ 6370) km where h (in km) is the...

  2. 當有一大串形容詞放埋一齊時,習慣上係有固定次序o既,點解要咁就真係考起,但你要講英文,就只能夠跟從呢個習慣。 根據 Michael Swan 著,Practical English Usage (p11, Oxford 2005),次序為: Size > Age >...

    分類:社會及文化 > 語言 2007年08月25日

  3. Answer : E 任何物件於地球表面,都受到gravitational force (g) ge 影響。Gravitation force會向住地心 (earth core) 拉住件物件。 而你亦都應該學左 Gravitation force = mg 所有物件都有一個Gravitation force (mg) 向下拉 如果該物件係置於地面上...

  4. You have some information missing. How much does its velocity decrease? As far as I remember this question, the velocity should decrease from 30 m/s to 20 m/s in 100 m. So, I will use this to do the question. Initial velocity, u = 30 m/s Final...

  5. Use indexOf(String str, int fromIndex) method of the String class. It returns the index of the first occurrence of the substring within the searched string, starting from the specified index. i = myString...

  6. Time needed for reaching the MAXIMUM velocity : u=0, v=10ms^-1, a=3.3ms^-2, By v=u+at,10=0+3.3t t=10/3.3 s distance of the runner's velocity change from 0 to 10ms^-1 : By v^2-u^2=2aS, 10^2-0=2(3.3)S S=100/6...

  7. A man standing in a stationary lift releases a stone. The stone takes t seconds to reach the floor of the lift. If the lift is moving downwards with constant velocity instead of being stationary A.The stone...

  8. friction compensated = 冇 friction 呢個net force. 因為如果你係平面推架車仔, 佢會有個friction 阻住你, 令你冇咁易推(net force 小左). or 你推完個friction 會整停佢. 但個斜路 佢係有個force 向下, 係mgsinx 咁當佢呢個mgsinx 同個木版gei friction 一樣, 咁佢就冇net force , 咁就好似冇左 令佢減速gei...

  9. A car travels from town A to town B. It first moves at a speed of 60km/h for 20 minutes and then at 80km/h for the rest of time. What is the car’s average speed if the distance between town A and town B is 60km...

  10. S(t) = ut + 0.5at^2 where S(t) is a function of t and equal to distance (in metre) travelled after t seconds with given initial speed of u and acceleration of a for this question, u = 20ms-1 and a = -1.5ms-2 (deceleration) After 3 seconds, the distance...