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  1. ... physical adress every page table address occupies 4 byte, so PDE + PTE has 4 * 2 ^10 * 2^10= 4Mbytes...

  2. ...圖片參考:http://homepage.ntu.edu.tw/~d90622003/pic/snap315.gif 程式如下 Dim occupied (4) As Boolean Dim t1(4), t2(4), t3(4) As Date...

  3. ...that unlike a struct, the variables a_number.i and a_number.l occupy the same location in memory. union int_or_long { int i; long l; } a_number...

  4. ... adopt dynamic mapping method ( Every User process occupies 4K PDE and PTE adopts dynamic mapping dependent...

  5. ...the second column dominates the RAM place from A[1, 3] occupies higher address than A[2, 2]. From A[1:j, 1:k] we know...

  6. ...to compile and run the following code 將會出現什麼? 3) One button occupying the entire frame saying Bye 一個按鈕佔用整個畫面且出現 Bye...

  7. ...:Slot XXX is already occupied by (XXX物品或方塊) when add (XXX物品或方塊) 此為 " I...

  8. ORG 00 MOV A,#0FFH QQ: MOV P1,A CLR A CALL DELAY MOV P1,A CLR A...

  9. 這只是簡單的數學問題 X(50) 放在address 1000h 又每一個element 是4 個bytes 所以 X(51) 放在address 1004h X(52) 1008h X(53) 100Ch .. X(300) 放在1000h + (300-50)*4 = 13E8h

  10. 1.(b) 2.(a)6 3.(d) (0,0) (0,1) (0,2) (0,3) ........................ 1982 (1,0) (1,1) (1,2) (1,3) ........................ 1984 (2,0) (2,1) (2,2) (2,3) ........................ 1986 (3,0) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (3,7) (3,8) ........................ 1988 + 12 + 12 + 12 + 12 + 12 = 2048 (4,0) (4,1) (4,2) (4,3) ................ 1978 1990 ← 差12 (5,0) (5,1) (5,2) (5,3...