...disease) + P(four have disease) + P(five have disease) (They are mutually exclusive events) = 5C3 * (1/5)^3 * (1 - 1/5)^2 + 5C4 * (1/5)^4 * (1...
...though the IRR is smaller ASSUMING they are mutually exclusive . Otherwise, BOTH should be adopted as both NPV ...
分類：商業及金融 > 其他 - 商業及金融 2007年12月11日
...probability(條件概率) Multiplication law of probability(概率乘法定律) Mutually exclusive events(互斥事件) Complementary event(互補事件) Certain...
...often unconscious, resulting from the opposition or simultaneous functioning of mutually exclusive impulses, desires, or tendencies. 4. Opposition...
...sugar) = 4/16 X 3/15 = 1/20 As the above events are all mutually exclusive , so the required probability = P(2 of the same kind) = 1/12 + 1/40...
... required) (atmost 4 draws and 5 draws are mutually exclusive ) = 1 – (4 / 6)(3 / 5)(2 /4)(1 / 3) = 14 / 15 The answer is...
...3/4 Another solution: Since X,Y,Z are mutually exclusive , then P(X U Y U Z) = P(X...
...) = 0.35 0.041 = 0.01435 Since the 2 events are mutually exclusive , so P(C wins) = 0.90146 + 0.01435 = 0.91581
maybe the cost of the two projects are different, or the capital comes from different sources, e.g. equity & bond.
分類：商業及金融 > 其他 - 商業及金融 2009年01月22日
