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aH = bH => (ab^-1)H = eH => ab^-1 is in H => H(ab^-1) = He => Ha = Hb
Proof. Let f_k_j be a subsequence of f_k converging to f a.e. By Fatou...
Let x1=y1-y3, x2=y2-y3. Then x1, x2 are solutions to the homogeneous...
Let φ be a test function. Since f = 1(0,1) a.e., we have 〈f ', &phi...
...x|<ε 即 x(N+1), x(N+2), ... contained in the B(X, x)=ε (<=) 設B(X, x)= r...
http://frankmath.cc/UCD/HWC1.pdf 看一下第三題,第三題就是你的問題了。 還好現在都有習慣把他打起來,這樣累積起來,問題要是重複,答案也可以重複使用。阿豪你也試著打Latex吧。
let in 相關
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