... the action in progress (that is, the action in progress is intercepted by the action of "see")
Sol x^(1/2)+y^(1/2)=c^(1/2) (1/2)x^(-1/2)+(1/2)y^(-1/2)y’=0 x^(-1/2)+y^(-1/2)y’=0 y^(-1/2)y’=-x^(-1/2) y’=-(x/y)^(-1/2)=-(y/x)^(1/2) Set L:y-b=-(b/a)^(1/2)*(x-a) a^(1/2)+b^(1/2)=c^(1/2) When x=0 y-b=-(b/a)^(1/2)(-a) y=b+(ab)^(1/2) When y=0 0-b=-(b/a)^(1/2)*(x-a) X-a...
...:C4-AVERAGE(C2:C4))^2) =0.796482 b的函數: = INTERCEPT (B2:B4,C2:C4) 或 =AVERAGE(B2:B4...
...:A3) 計算結果為 0 , 故迴歸直線斜率為 0 D2 輸入 = INTERCEPT (B1:B3,A1:A3) 計算結果為 2.33333333333333 , 故迴歸直線...
...curve √x + √y = √c (in the first quadrant). The sum of the x- and y- intercepts of L is ? Solution: √x + √y = √c Differentiate...
...b = (b/a)(x - a) a(y - b) = b(x - a) ay - ab = bx - ab ay = bx y = (b/a)x + 0 y- intercept of the normal line at (a, b) = 0 Hence, the normal line at (a, b) passes...
...投籃 putback tendency=補籃意識 flashy pass tend=花式傳球 foul tendency=犯規意識 pass intercept tend=中斷傳球意識 on ball steal tend=搶斷意識 contested shot tend= 高難度...
...εi)/σi² = σi²/σi² = 1 只留意這個更改了的模型沒有 intercept term 截數項。 這樣再作 OLS 線性廻歸 (沒截數項的版本) 就可以得出...