Yahoo奇摩 網頁搜尋

  1. ...the Derivative And the Mean Value THM 4. Integrals 5. Applications of Integrals 6. Transcendental...

  2. ...the relation between quantity and energy, this both are the both sides of the integral wholes, can convert each other, this cause nuclear energy of realization.(the loss of...

  3. ...唸。   本書能夠精簡下來,有一個很大的原因是作者把Riemannian Integral 給合併到Riemann-Stieltjes Integral 去了(也就是沒有...

  4. ... erected in 1883. Today the statue decoration is an integral part of the King Kamehameha Celebration. A ...

  5. ...建立了一些基本概念並發現了著名的「柯西積分定理」(Cauchy's Integral Theorem)。1828年高斯出版了《關於曲面的一般研究》,全面、系統地...

  6. 1.設 t = lnx , dt = 1/x dx 所以原式等於∫1+lnx/xlnx dx = ∫1+ t / t dt = ln | t | + t + c = ln lnx + lnx + c 2.直接利用反導函數 [sin-1(x)的微分為1/ √(1-x^2)] ∫√1-u^2 du [範圍0~1]=sin-1u [範圍0~1] [註:sin-1為arc sin之意] 所以答案等於π/2 - 0=π/2 3.也是直接利用反導函數 [cosh-1(x)的微分為1...

  7. ... you all the way with pleasure and comfort of the journey, Clorts become an integral part of your strong helper. 讓愛心力量協助更多需要幫助的弱勢朋友,讓...

  8. (a) ∫1/(x^2+1)^2 dx 令 x = tan(z),則 x^2 + 1 = sec^2(z),及 dx=sec^2(z) dz. ∫1/(x^2+1)^2 dx = ∫sec^2(z)/sec^4(z) dz = ∫cos(z)^2 dz = ∫(1+cos(2z))/2 dz = (z/2 + sin(2z)/4). 因為z=arctan(x), sin(2z)=2x/(x^2+1),故 ∫1/(x^2+1)^2 dx = (arctan(x) + x/(x^2+1))/2. (b) ∫(x^2-x)/(x^2+1)^2 dx (x^2-x)/(x^2+1)^2=(x^2+1-x-1)/(x^2+1)^2 = 1/(x^2+1) - x/(x^2+1)^2 - 1/(x^2...

  9. ...1690年發表於Actaeruditorum)中,我們第一次遇到微積學意義上的" integral "(積分)這個字,萊布尼茨曾經稱積分為求和計算(calculus summatorius...

  10. 1. -1/4 ln(x+2) + 1/4 ln(x-2) 2.?? 3. - ln2 + 3/2 4. 1/3 (1-1/e) 5. 1 很抱歉唷 因為我等級不夠 不能幫你貼我的計算過程 我只能給你答案了 如果你想知道過程就上及時通問我吧 我白天都會上線 tommiaomiles@yahoo.com.tw