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  1. ... eye of the storm wanna cry in the morn Oh, oh You're fine for a while But you start To lose controlHe's there in the dark ...

  2. int a = 1; while ( a <= 9) { int b = 1; while (b <= 9) { //兩個if條件做同樣的事情,so合併在一起就好,在一起,在一起,在一起.... if( a == Integer.parseInt(args[0]) || b == Integer....

  3. ...整數),char(字元or字串),float(浮點數),double(雙浮點數) 迴圈的部分大概就 for (例: for ( a =0; a <b; a ++)....) do... while (例:do... while (執行迴圈的條件)) while (例: while (執行迴圈的條件)) P.S...

  4. for (;;){ } =========== while (true){ } =========== do{ } while (true);

  5. 我用下面方式也可以算,與你答案相同 >> a =2.^(1:63); >> sum( a ) ans = 1.8447e+019 while 撰寫時進入迴圈時如果不加上b=b+1的話,我輸入 end下一行卻沒跳出迴圈出現...

  6. 改成 while : moji=c1 -1 ; while (moji++<c2) printf("%c", moji); 改成do- while : moji=c1; do{ printf("%c", moji); } while (moji++<c2); 如果...

  7. ...b=7; while ( a <=9) { while (b<=9) { cout...quot; << a << "...pause"); return 0; } 我另外給你 for 版的: #include<cstdlib>...

  8. ...quot; For a = 1 To 9 For b = 1 To 9 TextBox1... & b & "x" & a & "=" & b * a & ... a '▲▲第二小題(2. while ... end while ): TextBox1....

  9. ...意思是要不斷的重複,應修改成如下: WriteIns(0x01); //清除LCD while (1) { char a ; for ( a =0; a <7; a ++) { while (RI==0); RI=0...

  10. ...條件判斷式 ; 更新敘述) {執行敘述} while (條件判斷式) {判斷為真執行的敘述} 所以 for ( a =1 ; a <=9 ; a ++) 轉成 while 因該是 a =1; while ( a <=9) a ++; 還有 c= a *b; printf("%d*%d...