... are 3 forces acting on crate B The weight (downward), normal reaction (upward) ... = M(g+a) ----------- (1) Consider crate B, Rb - (Ra + mg) = ma i.e. Rb...
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... the location. For the time: The only force acting on the crate is the gravitational pull. (Air resistance is neglected here...
Let m be the mass of crate , then the component of the crate 's weight normal to the ramp is mg cos 58...of weight parallel to the ramp is mg sin 58 and therefore, the net force on the crate is: mg (sin 58 - 0.35 cos 58) with acceleration equal to: g (sin 58 - 0.35 cos...
...the worker along 32° below the horizontal, A force of Fcos32∘apply to the crate in horizontal direction, since the crate moves at constant velocity, total force = 0...
Let a be the angle between the motion direction of the crate and the force F1. Hence, (F1).sin(a) = (F2... to be 10 m/s^2 Therefore, acceleration of the crate = 45.5/22.62 m/s^2 = 2 m/s^2
... 1.a bunch of grapes 2.an ear of corn 3.a cube of sugar 4.a crate of beer 5.a pack of writing paper 6.a punnet of strawberries 7...
...1/2).(2.6)v^2 + 0.2223 = 0.4336 v = 0.403 m/s 2. Potential energy of crate on top of ramp = 1520 x 8sin(25) J = 5139 J Kinetic energy of...
