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  1. ...瀏覽器是否支援 http://blog.miniasp.com/post/2008/03/Flash-Intro-need- consider -more-than-detection.aspx 圖片參考:http://tw.blog.yahoo.com/photo/photo.php?id=LrW...

  2. ... considerations are integral part of system quality, thus should be considered together. I will reply when I have time in a few days. 2009-11...

  3. when n = 0 , 2^ ( 0 + 1 ) - 1 = 1 滿足 when n = 1 => T ( 1 ) = T ( 0 ) + 2^( 1 ) = 1 + 2 = 3 = 2^ ( 1 + 1 ) - 1 suppose when n = k T ( k ) = 2^ ( k + 1 ) - 1 when n = k + 1 => T ( k + 1 ) = T ( k + 1 - 1 ) + 2^( k + 1 ) = T ( k ) + 2^( k + 1 ) = 2^ ( k + 1 ) - 1 + 2^ ( k + 1...

  4. x := 1; i := 1; while (x < 1000) do begin x := x * 2; i := i + 1; end; init x=1, i=1 ------------------------ loop 1 , x=1 < 1000, true x = 2, i=2 ------------------------ loop 2, x=2 < 1000, true x = 4, i=3 ------------------------ loop 3 , x=4 < 1000, true x = 8, i=4...

  5. 左傾樹為二元樹 它如果不是空的 則對每一內部節點x shortest(left_child(x)) ≧ shortest(right_child(x)) 既然right path已經有r nodes 最差的狀況即為全部都是在右邊 因此整顆complete tree才可符合 Leftist tree 需要 : 2^(r+1)-1

  6. 圖片參考:http://farm4.static.flickr.com/3399/3274137516_9bd861997e_b.jpg 幫你畫出甘特圖以及算出 Avg. Waitting time了 有問題請再發問

  7. typedef struct X {int d;struct X *nxt;} X; X *m_th(X*x,int m){for(;m>0&&x;--m,x=x->nxt); return x;} int swap_mn(X*x,int m,int n){ int a,b; X*z,*y; for(a=(m>n)?n:m,y=x;a>0&&y;y=y->nxt,--a); for(b=(m>n)?(m-n):(n-m),z=y;b>0&&z;z=z->nxt,--b); if(y&&z){ a=y->d; y->d=z->d...

  8. 答案是 x = 40 和 y = 20。簡單來說,對於 change() 方法的傳入參數 x 和 y 是把 copy 的值傳進去,而不是把變數本身,因此不管方法內對 x, y 動什麼手腳,都不會影響到 main() 中宣告的 x, y,因此在印出時該兩值不變。

  9. 很明顯的就是連線字串有問題... example: connstr = “Driver={MySQL ODBC 3.51 Driver};server=localhost;” & “UID=username;PWD=password;database=dbname;Option=4;” 自己在修改一下吧...

  10. Q1. Dynamic programming: func(0) = 1 func(1) = 0 + 1 func(2) = 1 + 1 = 2 func(3) = (1+2) + 2 = 5 Q2. The most frequent executed statement is the body of the for loop. Let s(k) = 1+2+...+k if k >= 1, s(0) = 0, which is the function of the for loop...

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