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  1. ... = (100 - 15.5)% = 84.5% 2015-04-02 20:14:05 補充: sorry, a mistake in the calculation on the last 3 lines. The following is the right one...

  2. (a) Force F = (4.77x10^-18).(9.86x10^6).(4.48) N (b) option a (c) Acceleration a = F/1.88x10^-27 m/s^2 [where F is the force found in (a)] (d) Radius = (1.88x10^-27).(9.89x10^6)^2/F

  3. de Brogie wavelength = 6.63x10^-34/square-root[2 x 50x10^3 x 1.6x10^-19 x 9.1x10^-31] m = 5.49x10^-12 m Incident angle = 50/2 deg = 25 deg Hence, 2d.sin(25) = 5.49 x 10^-12 where d is the atomic plane spacing d = 6.5 x 10^-12 m 2013-10-22 23:13:20 補充: Your suppl question. It...

  4. 因爲你淨係要方程式,無需要數字,如果你有比數字,我可以幫你計,如果你要我幫你計,vr29w2hl@yahoo.com.hk 方程式如下 : 第一步 先將R1同R2以並聯方式加起來=Ra 再將R3同R4以並聯方式加起來=Rb 接下來將Ra同Rb以串聯方式...

  5. (c) The heat gain by the dripping water in 1 sec = (20/1000)x 4200 x T where T is the rise in temperature of the water, and 4200 J/kg-K is the specific heat capacity of water Heat generated by the drill = 2500 x 0.6 J/s The temperature of the...

  6. 圖片參考:http://imgcld.yimg.com/8/n/AF03901095/o/701110240002613873484121.jpg   So, det(A) = a^n + a^(n-1) b + a^(n-2) b^2 + ... + a b^(n-1) + b^n  

  7. 圖片參考:http://imgcld.yimg.com/8/n/HA00041588/o/701110020064913873470670.jpg Check whether my answer is the same as your standard solution.

  8. Rewriting (1) as: m1 (u - v1) = m2v2 ... (3) and (2) as: m1 (u2 - v12) = m2v22 (Cancelling 1/2) m1 (u - v1)(u + v1) = m2v22 ... (4) Dividing (4) by (3): u + v1 = v2 Sub into (1): m1u = m1v1 + m2(u + v1) m1u = m1v1 + m2u + m2v1 (m1 - m2)u = (m1 + m2)v1 v1 = (m1 - m2)/(m1 + m2) Then v2 = u + v1...

  9. So where is Part B? 2009-11-15 16:11:15 補充: By the equation, E= mcT', where T' is the change in temperature T' = E /(mc) = E/ (DVc) (since m = D*V) = 3390000 / (1.3*400*1030) = 6.32...

  10. By equation, E = m l, where E is the energy supplied, m is the mass, and l is the specific latent heat of fusion of water. Thus, 14400 = (0.05 - 0.01) * l l = 360000 (J/ kg )