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  1. .... of. periods ... 15.3 Products of neutralization. ... 15.8 Calculation on volumetric ...www.cytss.edu.hk/chem/schedule/ ts4.pdf - 20k - 以html格式檢視...

  2. ...0.65-0.6)v=9 (-140)*(0.05)=9 (-7)=-2 2007-01-28 23:59:59 補充: my calculation is that.a)v=u plus at u=0(release from rest), a=15, t=0.6v=0 plus 15(0...

  3. ... (.08 to .20 inches) a year. Until now, the best calculations differed by 1.8 millimetres a year. That doesn't sound...

  4. ...amp; 13; median= (vi) 13 8.There is a mistake in the following calculation .Correct the mistake. Data: 13 , 21 , 5 , 4 , 18 , 33 , 17 , 6 , 4 [new...

  5. 1. 0.306 2. 1.63 3. 0.670 4. if √(sin60.8tan60)+2(cos60)^2 = 1.73 if √(sin60.8)*tan60+2(cos60)^2 = 2.12 5. 55.2 6. 75.9 7. 16.2 8. 41.4 9. 68.0 10. 27.4

  6. The equation should be X (1+10%) (1-10%) = X The question means increment by 10% is X (1+10%) <= New amount Then the increased amount decrease by 10%, i.e. the new amount times (1-10%) So, it should be...

  7. As follows: 圖片參考:http://i238.photobucket.com/albums/ff245/chocolate328154/Maths374.jpg?t=1218464268

  8. 1. When a number x is increased by 10%, the new value will be (1+10%) x = 1.1x When a number y is decreased by 10%, the new value will be (1-10%) y = 0.9y So when a number x is increased by 10% then...

  9. a. H2SO4+2NaOH->2H2O+Na2SO4 b. Temperature of the reaction mixture rise, because the reaction is exothermic. c. H2SO4: 60/1000*0.5=0.03mol NaOH: 200/100*0.2=0.04mol d. According to equation, no. of mol of H2SO4: no. of mol of...