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Suppose room temp. = 298 K: PV = nRT 1.5 x 105 x 1 = n x 8.314 x 298 n = 60.5 moles Mass of He gas + balloon = 60.5 x 4 + 100 = 342.17 g Mass of air displaced = 60.5 x 28.8 = 1744 g (Take molar mass of air = 28.8 g/mol) So the balloon...

你的題目不全,沒提前段,其實它主要的意思是問水蒸氣的分壓變化, 不管你將壓力加到多高,他的水蒸氣分壓都是以溫度來決定的 2014-01-20 23:49:07 補充： 在25度C,水的蒸氣壓為0.031kg/cm2,也就是其分壓

電場公式 E = kQ/r^2 所以在 x 點的電場 E = kq( 2 / x^2 - 1 / (x-6)^2 ) (a)他要你算出 x = 正負0.5m時的電場 (應該是吧，不確定，還是每隔 0.5m 算一次)，總之就是把數字代進去算而已 (b) E = 0 = kq( 2 / x^2 - 1 / (x-6)^2 ) => 2 / x^2 = 1 / (x-6)^2 => 2( x^2 - 12x +36) = x^2 => x...

Let iron be 1, water be 2. From Energy Balance, 圖片參考：http://imgcld.yimg.com/8/n/AF03901095/o/151010040318113872074410.jpg 圖片參考：http://imgcld.yimg.com/8/n/AF03901095/o/151010040318113872074411.jpg 註：鐵的積分是從T1積到Te，水的...

...of the coil... I am now even more than 80% sure that my answer for calculating the energy loss is correct. 2007-02-28 21:00:39 補充： I will copy...

算能量啊 二分之一mv平方 所以(1/2)1000*88平方 和(1/2)1600*88平方

http://www.wretch.cc/album/show.php?i=springalbert&b=3&f=1879787748&p=180 2013-04-02 18:24:04 補充： 趕著接小孩 字醜 忍著點看...

(1) With reference to the diagram below: 圖片參考：http://i117.photobucket.com/albums/o61/billy_hywung/Nov07/Crazymech9.jpg (2) With reference to the diagram below: 圖片參考：http://i117.photobucket.com/albums/o61/billy_hywung/Nov07/Crazymech10.jpg...