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  1. Probability of defective bulb = 5% = 0.05 No. of bulbs in a box = 15 This is binomial...95 = 0.7125, so s.d. = sqrt 0.7125 = 0.8441. (b) P(Exactly 1 defective bulb in a box) = (15C1)(0.05)(1 - 0.05)^14 = 0.36576 No. of boxes...

    分類:科學及數學 > 數學 2011年10月25日

  2. Use filament bulb as the light source. This would eliminate stroboscopic effect. The reason for...an ordinary incandescent filament bulb operating on a 50 Hz ac supply, the bulb delivers light during the entire period of the waveform. At the ...

  3. when bulb X burns out, the total resistance of the circuit increases, so..., the reading of the ammeter will decrease. let the resistance of bulb Y = R the brightness of the bulb Y is related to...

  4. The brightness of each light bulb depends on the voltage across it. The higher the voltage, the...

  5. First, let a be the number of bulbs produced by production line A. Let...25b=-24x b=(24x)/25 So, the number of bulbs produced by production line B is...

    分類:科學及數學 > 數學 2015年01月14日

  6. light bulbs in the 2nd and 3rd terminal will still light up!! the first terminal is...complete circuit, 好似無左條電線咁, 咁何來D electrons會去the light bulb in the first terminal 呢?! 在上述情況,要出現short circuit,那 light bulb ...

  7. ... Ia = 1/2 * I 所以一個in series 既curcut本身有一個light bulb 係到之後加多個light bulb ,個current會變細左 希望解答到你 ^^

  8. 1.a.What will happen to bulb B? Since the copper wire by-passed bulb A, leaving... by the copper wire. There is no current flowing through bulb A. c.What will happen to the reading of the ammeter? The...

  9. ...circuit giving brighter light. Because the voltage across each bulb would be higher - source voltage. For series circuits, the voltage...

  10. 2.用light bulb 同兩種電池的牌子 3.長時間開住2個light bulb ,然後量度時間。 電池 -----------------+-+- --------------light bulb I l I...

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