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  1. 1. Bisection (二分法) function r = bisect (fun,xb,verbose) xeps = 1e-6...x; f(2) = x.^3-x; 4. main test % main test clear all clc x1 = bisect (@func,[1,1.5],0) x2 = secant(@func,1,1.5...

  2. ...0.4240, x=2.22120, x=4.7742(這點似乎誤差太大) 請自行嘗試二分法  >> x= bisect (f,[-1,0],0.01)x =   -0.4180二分法程式function r = bisect (fun,xb,xtol,ftol,verbose)% bisect ...

  3. 本題用二分逼近法解根 (1.920822) Public Sub bisect () Dim a As Single, b As Single, c As...

  4. 本題的低限 請輸入 3 本題的高限 請輸入 4 Public Sub bisect () Dim a As Single, b As Single, c As...

  5. ...---------------------------- 1. 二分法 function r = bisect (fun,xb) xeps = 5*eps; feps = 5*eps;a = xb(1); b = xb...

  6. ...1. 二分法 function r = bisect (fun,xb) xeps = 5*eps; feps = 5*... roots and singularities • Bisection is robust, but converges slowly • ...

  7. ...我利用我手邊兩個不同學者(不同數值分析課本來的)寫的二分法程式執行>> bisection (f,-4.9,-4.85,1e-8,1000)ans =   -4.8701>> bisect (f,-4.9,-4.85,1e-8...

  8. ...為我的程式碼, 但不能有while或for loop而只能用"疊切"法, 可惜的是, bisection 一定要用疊代(就是一定要用while 或 for loop), 是否可以請您再詳細說明什麼是...