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...1} dA; call it A(S) 2. the the centriod of Ｓ=(x0, y0), where x0 = 1/(A(S.... 以上是你要的[被積分函數 是什麼] Using the transmation u＝xy,v＝y/x => = x=(u/v)^(1/2...

... a p-series p=2, thus it is conv. Ans: the interval of conv. is |x-3|^2 <= 1/5, or 3-1...3+1/√5 2010-06-18 00:16:38 補充： We can use the Ratio test too. lim(n->∞) |a(n+1)/a...

...125=2.4E(x^2)= 0^2* 1/125+1^2*12/125+2^2* 48/125+3^2* 64/125=6.24 (b) use the results of part (a) to determine the value of E[(3x+2)^2]E[(3x+2)^2]=E(9x...

吼! (4000+1)(4000-1) =4000ㄉ平方-1平方 =15999999

... this case, there are two reasons why I choose to use the method of limit point. First, we cannot easily control the complement of A...

... of conv.= e/3 2010-06-22 10:53:39 補充： The major part of terms of the series is power fn. so we can use the root or ratio test. 2010-06-27 02:29:08 補充： 本題若不用Stirling...

1 set the number of classe 6A is X then boys:3/7X...3minutes i.e the speed of john is 9/3=3 times of the speed of mary than mary would spend another 9minutesx3=27 minutes...

...axis, each point (x,y) will generate a circle of radius |y|, in a second parameter v , (x,y) will generate the circle (x,ycosv,ysinv), v=0 to 2pi. ... the curve C would generate a surface, using two paremeters u and v: ...